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Solving routine problem involving factors, multiples and divisibility rules for 2,3,4,5,6,8,9,10,11 and 12 solve the word problem. Some students of Malagasang 2 Elementary School can pose for a snapshot in rows of 6 or 7. What is the least number of students there can be? 1.] What is asked in the word problem? 2.] What are the given facts? 3.] What operation is needed to solve the word problem? 4.] What is the number sentence? 5.] What is correct answer?

1 Answer

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Final answer:

The least number of students who can form rows of either 6 or 7 is 42, which is the Least Common Multiple (LCM) of 6 and 7.

Step-by-step explanation:

The word problem is asking for the least number of students who can form rows of either 6 or 7. The facts given are that the students can be arranged in rows of 6 or 7, which means we are looking for a number that is a common multiple of both 6 and 7. To solve this problem, we need to employ the operation of finding the Least Common Multiple (LCM). Therefore, the number sentence will be the calculation of the LCM of 6 and 7. To solve for the LCM of 6 and 7, we list the multiples of each until we find the smallest number that appears in both lists:

  • Multiples of 6: 6, 12, 18, 24, 30, 36, 42, …
  • Multiples of 7: 7, 14, 21, 28, 35, 42, …

The smallest common multiple is 42, so the least number of students there can be is 42. We ensure this answer is reasonable: 42 is divisible by both 6 and 7 and is indeed the smallest number that meets this requirement.

User Sebastian Kreft
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