Question

Uranium-235 undergoes a fission process. What is the value of 'x' in the equation: 235U + on → Cs + Rb + x)n?

a) 90
b) 92
c) 93
d) 94

Answer 1

The value of 'x' in the equation is a. 90.

Step-by-step explanation:

In the fission process of Uranium-235, the balanced nuclear equation is 235U + on → Cs + Rb + x)n.

Since Uranium-235 has an atomic number of 92, it means it has 92 protons. In the equation, Cs represents Cesium, which has an atomic number of 55. And Rb represents Rubidium, which has an atomic number of 37.

Therefore, the value of 'x' in the equation is the atomic number of Uranium-235 minus the atomic numbers of Cesium and Rubidium, which is 92 - 55 - 37 = 0.

So, option (a) is correct: 90.