Question

if at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 4.80 v/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time? express your answer in teslas.

Answer 1

The magnitude of the magnetic field corresponding to an electric field of 4.80 V/m in a plane electromagnetic wave is 1.60 × 10^-8 T, calculated using the speed of light and the known equation relating electric and magnetic field strengths in an electromagnetic wave.

Step-by-step explanation:

To determine the magnitude of the magnetic field of a plane electromagnetic wave at a particular instant and point in space where the electric field has a magnitude of 4.80 V/m, one can use the relationship between the magnitudes of the electric field (E) and the magnetic field (B) in an electromagnetic wave, given by the equation c = E/B, where c is the speed of light in a vacuum (approximately 3 × 10^8 m/s).

By rearranging the equation to solve for B, we get:

B = E/c

Substituting the given values:

B = 4.80 V/m / (3 × 10^8 m/s)

The magnitude of the magnetic field (B) is thus 1.60 × 10^-8 T (Tesla), at that particular point in space and instant in time.