Question

hydrogen chloride gas and oxygen react to form water vapor and chlorine gas. what volume of chlorine would be produced by this reaction if 9.29 l of oxygen were consumed? also, be sure your answer has a unit symbol, and is rounded to the correct number of significant digits.

Answer 1

The volume of chlorine gas produced from the given reaction, with the consumption of 9.29 liters of oxygen, would be 18.58 liters.

Step-by-step explanation:

To determine the volume of chlorine gas produced from the reaction of hydrogen chloride gas with oxygen, we start by writing the balanced chemical equation for the reaction:

4 HCl(g) + O2(g) → 2 Cl2(g) + 2 H2O(g)

From the balanced equation, we see that 4 moles of HCl react with 1 mole of O2 to produce 2 moles of Cl2. Thus, the molar ratio between O2 and Cl2 is 1:2.

Assuming that the conditions of the reaction fall under standard temperature and pressure (STP), where 1 mole of any gas occupies a volume of 22.4 liters, we can use the ratio from the balanced equation to determine the volume of chlorine gas. Since 9.29 liters of O2 are consumed:

1 mole O2 : 2 moles Cl2
9.29 liters O2 : x liters Cl2

To calculate x, we set up a proportion:

x = (9.29 L O2 × 2 moles Cl2) / 1 mole O2

x = 18.58 liters Cl2

The volume of chlorine gas produced would be 18.58 liters, rounded to four significant digits to match the precision of the given oxygen volume.