Question

a parked car gets hit by a bus. the car has a mass of 900 kg. it is initially at rest. immediately after the collision, it is moving at 18 m/s. the collision occurs over 0.35 s. what is the average force on the car during the collision? group of answer choices 0.9 kn 46 kn 16 kn 111 kn

Answer 1

The average force on a car during a collision can be found using the equation Average Force = Change in Momentum / Time. By calculating the initial momentum, final momentum, and time of the collision, we can determine the average force. In this case, the average force on the car is approximately 46 kN.

Step-by-step explanation:

Given:

Mass of the car (m) = 900 kg

Initial velocity of the car (u) = 0 m/s

Final velocity of the car (v) = 18 m/s

Time taken for the collision (t) = 0.35 s

To find the average force on the car during the collision, we can use the equation:

Average Force (F) = Change in Momentum (Δp) / Time (t)

Momentum (p) is defined as the product of mass and velocity:

Momentum (p) = mass (m) x velocity (v)

Change in momentum (Δp) = Final momentum (pf) - Initial momentum (pi)

Initial momentum (pi) = mass (m) x Initial velocity (u)

Final momentum (pf) = mass (m) x Final velocity (v)

Substituting the given values:

Initial momentum (pi) = 900 kg x 0 m/s

= 0 kg*m/s

Final momentum (pf) = 900 kg x 18 m/s

= 16200 kg*m/s

Change in momentum (Δp) = 16200 kg*m/s - 0 kg*m/s

= 16200 kg*m/s

Substituting the values into the formula:

Average Force (F) = 16200 kg*m/s / 0.35 s

= 46285.71 N

Therefore, the average force on the car during the collision is approximately 46 kN.