Question

A golf ball is hit with an initial velocity of 40 fps using the formula h = -8t^2 + 40t, where t is time and h is the height. How high is the ball after 2 seconds?

Answer 1

The golf ball is 48 feet high after 2 seconds when we substitute t = 2 in the formula h = -8t^2 + 40t.

Step-by-step explanation:

To find how high the golf ball is after 2 seconds using the given formula h = -8t^2 + 40t, we substitute t with 2 seconds.

Substituting t with 2, we get:

h = -8(2)^2 + 40(2)

h = -8(4) + 80

h = -32 + 80

h = 48 feet

Thus, the golf ball is 48 feet high after 2 seconds.