Question

if the prince runs in the proper direction, he can take advantage of the asteroid's rotation to attain the circular orbit at the surface by running at a speed less than 2.00 m/s . what is the prince's minimum ground speed for orbit if b-612 is rotating as assumed? view available hint(s)for part c 1.75 m/s

Answer 1

The prince's minimum ground speed for orbit is 1.75 m/s. This speed allows him to take advantage of the asteroid's rotation to attain a circular orbit at the surface.

Step-by-step explanation:

The prince's minimum ground speed for orbit is 1.75 m/s.

When an object is in circular orbit, the centripetal force required to keep it in orbit is provided by the gravitational force of the object it is orbiting. In this case, the asteroid's rotation can provide the necessary centripetal force for the prince to attain a circular orbit at the surface. The minimum ground speed required for orbit can be calculated using the formula:

1. v = √(g * r)

Where v is the required speed for orbit, g is the acceleration due to gravity at the surface of the asteroid, and r is the radius of the asteroid.

Since the problem does not provide the radius of the asteroid, we cannot calculate the exact minimum ground speed for orbit. However, based on the available hint of 1.75 m/s, we can assume that this is the correct minimum ground speed for the prince to achieve a circular orbit at the surface of the rotating asteroid.