Question

if the throw of a follower is 10 mm, the cam rotates at 20 rpm, and the rise period is 90 degrees, what is the maximum acceleration of the follower, amax, assuming that the peak acceleration factor, ca, equals 4.888?

Answer 1

The maximum acceleration of the follower in the cam mechanism is determined using the given throw, rotation speed, and the peak acceleration factor, following the formula a_max = ca × (ω^2 × throw), where ω is the angular velocity in radians per second.

The maximum acceleration of the follower is 12.93 mm/s².

Step-by-step explanation:

To find the maximum acceleration of the follower, we need to calculate the maximum velocity first.

The maximum velocity can be obtained by multiplying the throw of the follower and the angular frequency. In this case, the throw of the follower is 10 mm and the cam rotates at 20 rpm (revolutions per minute).

The maximum velocity (vmax) = throw of the follower x angular frequency

= 10 mm x (20 rpm x 2π radians/1 minute)

To find the maximum acceleration (amax), we can use the peak acceleration factor (ca).

The maximum acceleration (amax) = vmax / ca

Substituting the values,

amax = (10 mm x (20 rpm x 2π radians/1 minute)) / 4.888

= 12.93 mm/s².