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a 0.5 l ballon has an unknown pressure, the volume of the ballon is decreased at constant temperature to 0.2l and the pressure is measured at 200 kpa what was the initial pressure in the balloon

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Final answer:

Using Boyle's Law, the initial pressure in the balloon can be calculated with the given final pressure and volume change. The initial pressure was found to be 80 kPa.

Step-by-step explanation:

To determine the initial pressure of the balloon, we can use Boyle's Law, which states that the pressure of a gas varies inversely with its volume when the temperature and the amount of gas remain constant (P1V1 = P2V2). Given that the volume of the balloon changes from 0.5 L to 0.2 L and the final pressure P2 is 200 kPa (kiloPascals), we set up the equation as follows:

P1 x 0.5 L = 200 kPa x 0.2 L

To find the initial pressure P1, we rearrange the equation and solve for P1:

P1 = (200 kPa x 0.2 L) / (0.5 L)

P1 = 400 kPa / 0.5

P1 = 80 kPa

Therefore, the initial pressure in the balloon was 80 kPa.

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