Question

a straight wire that is 0.45 m long is carrying a current of 3.5 a. it is placed in a uniform magnetic field of strength 1.30 t. if the wire experiences a force of 0.23 n, what angle does the wire make with respect to the magnetic field?

Answer 1

The wire makes an angle of approximately 0.087 radians or 5 degrees with respect to the magnetic field.

The angle between the wire and the magnetic field can be calculated using the formula for the magnetic force on a conductor. By rearranging the formula and plugging in the given values, one can solve for the angle using the inverse sine function.

Step-by-step explanation:

To calculate the angle between the wire and the magnetic field, we can use the formula:

F = I * L * B * sin(theta)

Where F is the force experienced by the wire, I is the current, L is the length of the wire, B is the magnetic field strength, and theta is the angle between the wire and the magnetic field.

In this case, we are given the values for F, I, L, and B. We can rearrange the formula and solve for theta:

sin(theta) = F / (I * L * B)

theta = arcsin(F / (I * L * B))

Plugging in the given values:

theta = arcsin(0.23 N / (3.5 A * 0.45 m * 1.30 T))

theta = arcsin(0.23 / 2.63) = 0.087 radians

Therefore, the wire makes an angle of approximately 0.087 radians or 5 degrees with respect to the magnetic field.