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a publisher reports that 57% of their readers own a particular make of car. a marketing executive wants to test the claim that the percentage is actually more than the reported percentage. a random sample of 180 found that 60% of the readers owned a particular make of car. is there sufficient evidence at the 0.02 level to support the executive's claim? step 4 of 7 : determine the p-value of the test statistic. round your answer to four decimal places.

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There is sufficient evidence at the 0.02 level to support the marketing executive's claim that the percentage of readers who own a particular make of car is actually more than the reported percentage of 57%.

Determine the p-value of the test statistic

To determine the p-value, we need to find the probability of getting a test statistic (z) as extreme or more extreme than the one we calculated in Step 3, assuming the null hypothesis is true. Since this is a one-tailed test (because the alternative hypothesis is only directional), we only need to consider the upper tail of the distribution.

Using a standard normal distribution table or calculator, we can find that the p-value for z = 1.96 is 0.0251.

Make a decision

Since the p-value (0.0251) is less than the significance level (0.02), we reject the null hypothesis. There is sufficient evidence at the 0.02 level to support the marketing executive's claim that the percentage of readers who own a particular make of car is actually more than the reported percentage of 57%.

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