Question

under certainwater conditions, the free chlorine (hypochlorous acid,hocl) in a swimming pool decomposes according to thelaw of uninhibited decay. after shocking his pool, bentested the water and found the amount of free chlorine tobe 2.5 parts per million (ppm). twenty-four hours later, bentested the water again and found the amount of free chlorineto be 2.2 ppm. what will be the reading after 3 days (thatis, 72 hours)? when the chlorine level reaches 1.0 ppm, benmust shock the pool again. how long can ben go before hemust shock the pool again?

Answer 1

To obtain a concentration of 3.0 ppm of chlorine in a pool, approximately 63.6 kg of chlorine must be added to a 5,000 gallon pool.

Step-by-step explanation:

To calculate the mass of chlorine needed to obtain a concentration of 3.0 ppm in a pool, we first need to convert the pool volume from gallons to kilograms.

Using the density of water, we can calculate the mass of water in the pool.

Then, we can use the concentration of chlorine in ppm to calculate the mass of chlorine needed using the formula:

Mass of chlorine = (concentration in ppm * mass of water) / 1,000,000.

For the given pool volume of 5,000 gallons and using the density of water, the mass of water in the pool is 21,200 kg. Plugging this into the formula, the mass of chlorine needed is approximately 63.6 kg.