72.2k views
2 votes
what will be the ph of a buffer solution prepared from 0.27 mol sodium acetate, 0.29 mol acetic acid, and just enough water to give 1.02 l of solution? use ionization constants from appendices h

1 Answer

4 votes

The pH of the buffer solution is 4.74.

The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:

The Henderson-Hasselbalch equation is a mathematical expression that relates the pH of a solution containing a weak acid (HA) and its conjugate base (A⁻) to the pKa of the acid.

The equation is commonly used in chemistry and biochemistry to understand and calculate the pH of a buffer solution.

pH = pKa + log([A-]/[HA])

where:

pKa is the dissociation constant of the weak acid

[A-] is the concentration of the conjugate base

[HA] is the concentration of the weak acid

In this case, the weak acid is acetic acid (CH3COOH) and the conjugate base is sodium acetate (CH3COO-).

The pKa of acetic acid is 4.76.

The concentration of sodium acetate is 0.27 mol/L and the concentration of acetic acid is 0.29 mol/L.

Plugging these values into the Henderson-Hasselbalch equation, we get:

pH = 4.76 + log(0.27/0.29)

pH = 4.74

Therefore, the pH of the buffer solution is 4.74.

User Mithra
by
7.9k points