Question

A projectile is fired at an angle of 30 degrees above the horizontal with a speed of 200 m/s in a region where g = 10 m/s/s. Neglecting the air resistance, what’s the speed of the projectile when it reaches when it reaches a height of 100 meters above the launch point? Do this with energy conservation.

Answer 1

The speed of the projectile when it reaches a height of 100 meters is 20 m/s.

Step-by-step explanation:

To find the speed of the projectile when it reaches a height of 100 meters, we can use the principle of conservation of energy. Since there is no air resistance, the only forces acting on the projectile are gravity and the initial velocity.

At its highest point, the projectile will have converted all of its initial kinetic energy into potential energy, so we can equate the two:

1/2 * m * v^2 = m * g * h

Where m is the mass of the projectile, v is the velocity at the highest point, g is the acceleration due to gravity, and h is the height. Solving for v, we get:

v = √(2 * g * h)

Substituting the given values, we find:

v = √(2 * 10 * 100)

= 20 m/s