Question

A coin is tossed 5 times. find the probability that none are tails

Answer 1

`( (1)/(2) )^5 = (1)/(32)`

Explanation:

The probability of "not a tail" is 1/2. The five tosses are independent, so the probability of "not a tail" 5 times in succession is

`\left((1)/(2)\right) \cdot \left((1)/(2)\right) \cdot\left((1)/(2)\right) \cdot\left((1)/(2)\right) \cdot\left((1)/(2)\right)`