Final answer:
To find the probability that at least six people have adequate earthquake supplies out of 11 surveyed residents, we can use the binomial probability formula.
Step-by-step explanation:
To find the probability that at least six people have adequate earthquake supplies, we need to consider the binomial distribution. The random variable X represents the number of people with adequate supplies out of 11 surveyed residents. Since the probability of an individual having adequate supplies is 0.3, we can use the binomial probability formula to calculate the probability of X being greater than or equal to 6:
P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) = binomcdf(11, 0.3, 6) + binomcdf(11, 0.3, 7) + binomcdf(11, 0.3, 8) + binomcdf(11, 0.3, 9) + binomcdf(11, 0.3, 10) + binomcdf(11, 0.3, 11) ≈ 0.5176
Therefore, the probability that at least six people have adequate earthquake supplies is approximately 0.5176. The correct answer is D) 0.5000.
To determine the probability that at least six individuals have adequate earthquake supplies, we need some additional information such as:
- The total number of individuals in the sample
- The probability of any one individual having adequate earthquake supplies
- Whether the events are independent
Without these details, we cannot provide a precise answer. However, I can guide you through the general approach that would be used if these details were known.
Assuming that we are dealing with a binomial probability situation where we have a fixed number of independent trials (n individuals) and each trial has only two outcomes (either an individual has adequate supplies or not), then:
Let:
- \( p \) be the probability that an individual has adequate earthquake supplies,
- \( q = 1 - p \) be the probability that an individual does not have adequate supplies,
- \( n \) be the total number of individuals.
The probability of having exactly \( k \) individuals with adequate supplies is given by the binomial probability formula:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]
Where \( \binom{n}{k} \) is the binomial coefficient, calculated as \( \frac{n!}{k!(n-k)!} \).
To find the probability of "at least" 6 individuals having adequate supplies, you sum the probabilities of having 6, 7, ..., up to n individuals having adequate supplies:
\[ P(X \geq 6) = P(X=6) + P(X=7) + \ldots + P(X=n) \]
The answer will be between 0 and 1, and you will round that to four decimal places as required.
Since you've provided a multiple-choice list, there is a chance that one of these options is correct, but without the specific details, we cannot confirm this.
If you provide the missing information such as the value of \( p \) and \( n \), a detailed probability can be calculated for the options given (A) 0.1250, (B) 0.2500, (C) 0.3750, (D) 0.5000. Until then, it is not possible to accurately answer which of these probabilities is correct.