Question

You are planning a graduation for your son. you decide to offer both a beef and a chicken meal at the party. the chicken dish costs 5 and the beef dish costs 7. there will be 250 people at the party the total cost of the food is 1500. how many chicken meals will there be? how many beef meals will there be?

Answer 1

By setting up a system of equations, we can determine there will be 125 chicken meals and 125 beef meals served at the party, with each meal type costing $5 and $7 respectively and a total cost of $1500 for 250 people.

Step-by-step explanation:

We are given that the total number of people at the party is 250, the chicken meal costs $5, and the beef meal costs $7. We also know the total cost for all meals is $1500. We can set up a system of equations to solve for the number of chicken meals (let's call this x) and the number of beef meals (let's call this y).

1. The total number of meals is equal to the number of people: x + y = 250.
2. The total cost of the meals is equal to the cost of chicken meals plus the cost of beef meals: 5x + 7y = 1500.

Now, let's solve this system of equations:

1. 5x + 5y = 1250 (multiply the first equation by 5)
2. 5x + 7y = 1500 (keep the second equation as it is)
3. Subtract the first equation from the second equation to solve for y: 2y = 250

Therefore, y = 125. This means there will be 125 beef meals.

To find the number of chicken meals, we substitute y back into the first equation:

x + 125 = 250

Hence, x = 125. There will also be 125 chicken meals.

So, for this graduation party, there will be 125 chicken meals and 125 beef meals.