Question

Sort the following complex ions by the magnitude of Î"o, with the largest Î"o at the top and the smallest Î"o at the bottom:

a. [Cr(CN)6]3-
b. [Mo(CN)6]4-
c. [Fe(CN)6]4-

Answer 1

To sort the complex ions by the magnitude of Δo, the largest Δo is at the top and the smallest Δo is at the bottom. The order is [Cr(CN)6]3-, [Fe(CN)6]4-, [Mo(CN)6]4-.

Step-by-step explanation:

The magnitude of Δo, or crystal field splitting energy, depends on the metal ion and its ligands. In this case, we need to compare the complex ions [Cr(CN)6]3-, [Mo(CN)6]4-, and [Fe(CN)6]4-.

The principle quantum number of the metal ion plays a significant role in determining the magnitude of Δo. Higher principle quantum numbers generally correspond to larger Δo values.

Therefore, we can rank the complex ions in order of increasing Δo as follows:

1. [Cr(CN)6]3-
2. [Fe(CN)6]4-
3. [Mo(CN)6]4-