Final answer:
The mass of AgCl produced, we need to determine the limiting reactant between AgNO₃ and AlCl₃. Using the given masses of AgNO₃ and AlCl₃, we calculate the number of moles for each reactant and determine the limiting reactant. From there, we can use the stoichiometric ratio to find the moles of AgCl formed and convert it to grams using the molar mass.
Step-by-step explanation:
To find the mass of AgCl produced, we need to determine the limiting reactant between AgNO₃ and AlCl₃. First, we calculate the number of moles for each reactant by dividing their mass by their molar mass. Then, we use the stoichiometric ratio from the balanced equation to find the moles of AgCl formed.
Finally, we convert the moles of AgCl to grams using its molar mass.
Step 1: Calculate the number of moles of AgNO₃:
Moles of AgNO₃ = Mass of AgNO₃ / Molar mass of AgNO₃
Moles of AgNO₃ = 4.22 g / 169.88 g/mol = 0.0249 mol
Step 2: Calculate the number of moles of AlCl₃:
Moles of AlCl₃ = Mass of AlCl₃ / Molar mass of AlCl₃
Moles of AlCl₃ = 7.73 g / 133.34 g/mol = 0.0579 mol
Step 3: Determine the limiting reactant:
The limiting reactant is the one that produces the lesser amount of moles. In this case, AgNO₃ is the limiting reactant.
Step 4: Calculate the moles of AgCl formed:
Moles of AgCl = 0.0249 mol AgNO₃ × (1 mol AgCl / 1 mol AgNO₃) = 0.0249 mol
Step 5: Convert moles of AgCl to grams:
Mass of AgCl = Moles of AgCl × Molar mass of AgCl
Mass of AgCl = 0.0249 mol × 143.32 g/mol = 3.57 g