Final answer:
To find the magnitude of average force exerted by the ball on the wall, we can use the concept of impulse. Using the given mass and change in velocity, we can calculate the impulse. Dividing the impulse by the contact time gives us the magnitude of the average force exerted by the ball on the wall, which is 20 N.
Step-by-step explanation:
To find the magnitude of average force exerted by the ball on the wall, we can use the concept of impulse. Impulse is the change in momentum of an object, and it can be calculated using the formula:
Impulse = Change in Momentum = m * Δv
where m is the mass of the object and Δv is the change in velocity. In this case, the ball rebounds with the same speed but in the opposite direction, so the change in velocity is 2 * (1.5 m/s) = 3 m/s. Using the given mass of 6 g (converted to kg), we can calculate:
Impulse = (0.006 kg) * (3 m/s) = 0.018 N·s
The magnitude of the average force exerted by the ball on the wall is equal to the impulse divided by the contact time, which is 0.9 ms (converted to seconds):
Average Force = Impulse / Contact Time = (0.018 N·s) / (0.0009 s) = 20 N
Therefore, the magnitude of average force exerted by the ball on the wall is 20 N.