Question

Anand needs to hire a plumber who charges an initial fee of $65 along with an hourly rate of $28. Anand would like to spend no more than $250. Let h represent the whole number of hours that the plumber works. How many hours of work can Anand afford?

a) h = 6
b) h = 7
c) h = 8
d) h = 9

Answer 1

Set up the equation
65 + 28h =250

Subtract 65 from both sides
28h = 185

Divide both sides by 28
H=6.6

It asked for whole hours. The answer is 6

Answer 2

Anand can afford 6 hours of work from the plumber.

Step-by-step explanation:

To find out how many hours of work Anand can afford, we need to set up an inequality based on Anand's budget. Let h represent the number of hours the plumber works.

Anand's budget is $250, which includes the initial fee of $65 and $28 per hour of work. So, the inequality is:

65 + 28h ≤ 250

To solve this inequality, we first subtract 65 from both sides of the inequality:

28h ≤ 250 - 65

28h ≤ 185

Then, we divide both sides by 28:

h ≤ 185/28

Using long division, we find that 185 divided by 28 is approximately 6.61. Since h represents a whole number, the maximum number of hours of work Anand can afford is 6 hours.