Final answer:
The equation of the parabola modeling the arch with a span of 140 meters and a maximum height of 14 meters, with its vertex at the origin, is y = -0.00285714286x^2 + 14.
Step-by-step explanation:
The student is asking for the equation of a parabola that models an arch with a span of 140 meters and a height of 14 meters, assuming the vertex of the parabola is at the origin. To find the equation of the parabola, we can use the standard form y = ax2 + bx + c, where the vertex is at (0, c), which in this case is (0, 14), and the parabola opens downwards. Since the arch is 140 meters wide and symmetric, the x-intercepts are located at (-70,0) and (70,0).
Considering the vertex form y = a(x - h)2 + k, with (h,k) being the vertex and since the vertex is at the origin (0,14), the equation simplifies to y = ax2 + 14. Next, we substitute one of the x-intercepts into the equation to solve for 'a'. Using (70,0):
0 = a(70)2 + 14
a = -14 / (70)2
a = -0.00285714286
Thus, the equation of the parabola is y = -0.00285714286x2 + 14.