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An automobile engine slows down from 3500 rpm to 1100 rpm in 2.7 s .

Options:
a) True
b) False

1 Answer

1 vote

Final answer:

The question asks for a conversion of an engine's slowing down speed from rpm to rev/s, and none of the given options match the calculated new speed. We find that the automobile engine's new speed is not in the options as the calculated deceleration (change in speed over time) does not correspond to any of the proposed speeds.

Step-by-step explanation:

The question pertains to a physics concept involving rotational motion and angular deceleration. Specifically, it asks whether a statement about an automobile engine slowing down from 3500 revolutions per minute (rpm) to 1100 rpm in 2.7 seconds is true, and what would be its new speed in revolutions per second (rev/s). To assess the accuracy of the statement, we calculate the change in speed and convert it to rev/s.

To find the angular deceleration, we first convert the speeds from rpm to rev/s:
Initial speed: 3500 rpm ÷ 60 = 58.33 rev/s
Final speed: 1100 rpm ÷ 60 = 18.33 rev/s

Now, the change in speed is the initial speed minus the final speed. Therefore, the change in speed (Δv) is 58.33 rev/s - 18.33 rev/s = 40 rev/s. Since this change occurs over 2.7 seconds, the rate of deceleration (Δv/Δt) is 40 rev/s ÷ 2.7 s = 14.81 rev/s2, which matches none of the options provided.

User Jos Dirksen
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