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The sides of the rectangle above increase in such a way that 10x ^+y ^2=10. At the instant when x=4 and y=3, what is the value of dy/ dt?


a. 1
b.2
c.√ 5
d. 5

User Lesleyann
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1 Answer

6 votes

Final answer:

The question is a related rates problem in calculus, but it cannot be solved without the rate of change of x with respect to time (dx/dt), which is not provided. Hence, it is impossible to determine dy/dt with the given information.

Step-by-step explanation:

The student has presented a related rates problem involving a rectangle changing dimensions over time. Given the equation 10x^2 + y^2 = 10 and the instantaneous values x=4 and y=3, we are asked to find the value of dy/dt.

To solve this, we'll take the derivative of both sides of the equation with respect to time (t), which gives us:

20x(dx/dt) + 2y(dy/dt) = 0

Given that x is increasing at a certain rate (which we don't know), dy/dt is the rate at which y is changing when x=4 and y=3. We can rearrange the equation to solve for dy/dt:

dy/dt = -20x(dx/dt) / 2y

However, we do not have the value of dx/dt, and it's not provided in the given information. Without dx/dt, we cannot calculate dy/dt.

Therefore, we are unable to solve for dy/dt as we lack sufficient information to determine the value.

User Ajdams
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