Question

Line C has an equation of y = (4/3)x - 9. Line D is parallel to Line C and passes through (-4,-4). What is the equation of Line D? Write the equation in slope-intercept form:

a. y = (4/3)x - 5
b. y = (4/3)x - 7
c. y = (4/3)x + 7
d. y = (4/3)x + 5

Answer 1

To find the equation of Line D, we need to use the same slope as Line C and the given point. Plugging these values into the point-slope form of a linear equation, we can determine the equation of Line D as y = (4/3)x - 8/3.

Step-by-step explanation:

To find the equation of a line parallel to Line C, we need to use the same slope as Line C, which is 4/3. Since Line D passes through the point (-4,-4), we can use the point-slope form of a linear equation to find the equation of Line D. The point-slope form is given by y - y1 = m(x - x1), where (x1, y1) is the given point and m is the slope. Plugging in the values, we get y - (-4) = (4/3)(x - (-4)). Simplifying the equation, we get y + 4 = (4/3)(x + 4). Rearranging the terms, we get y = (4/3)x + 16/3 - 4. Simplifying further, we get y = (4/3)x - 8/3. Therefore, the equation of Line D in slope-intercept form is y = (4/3)x - 8/3.