Question

Julian school is selling tickets for a play the tickets cost $10.50 for adults and $3.75 for students ticket sales for opening night total to $2071.50 the equation 10.58 3.75 feet or 2071.50 wear a is the number of adult tickets for nba is the number of students tickets sold can be used to find the number of a dog and a student tickets at 82 students attend how many tickets were sold

a. 120 adults, 82 students
b. 82 adults, 120 students
c. 100 adults, 80 students
d. 80 adults, 100 students

Answer 1

The number of adult tickets sold is 0 and the number of student tickets sold is 180.

Step-by-step explanation:

To find the number of adult and student tickets sold, we can solve the system of equations 10.50a + 3.75s = 2071.50 and a + s = 82, where a is the number of adult tickets and s is the number of student tickets.

Multiplying the second equation by 10.50, we get 10.50a + 10.50s = 855.

Subtracting this second equation from the first equation, we get 10.50a + 3.75s - (10.50a + 10.50s) = 2071.50 - 855.

Simplifying, we have -6.75s = 1216.50, which gives us s = 180. Dividing the original equation a + s = 82 by s = 180, we get a = 82 - 180 = -98.

Since it doesn't make sense to have a negative number of tickets, we can conclude that the number of adult tickets sold is 0 and the number of student tickets sold is 180.