Question

Consider the reaction: I2 (g) ⇌ 2I (g) with a Kc of 0.0011. In an equilibrium mixture, the concentration of I2 is 0.10 M. What is the equilibrium concentration of I?

a. 0.033 M
b. 0.0104 M
c. 0.00104 M
d. 0.0033 M.

Answer 1

To find the equilibrium concentration of I in the reaction I2 (g) ⇌ 2I (g) with a Kc of 0.0011, plug in the values into the equilibrium constant expression Kc = [I]^2 / [I2]. After solving for [I], the equilibrium concentration of I is 0.033 M.

Step-by-step explanation:

To calculate the equilibrium concentration of I in the reaction I2 (g) ⇌ 2I (g) with a Kc of 0.0011, we need the initial concentration of I2 and the equilibrium concentration of I2.

Given that the concentration of I2 is 0.10 M in the equilibrium mixture, we can use the equilibrium constant expression Kc = [I]^2 / [I2] to solve for the concentration of I.

Plugging in the values, we have 0.0011 = [I]^2 / (0.10). Solving for [I], we find that the equilibrium concentration of I is 0.033 M, so the correct answer is option a. 0.033 M.