Question

Consider the reaction: I2 (g) ⇌ 2I (g) with a Kc of 0.0011. In an equilibrium mixture, the concentration of I2 is 0.10 M. What is the equilibrium concentration of I?

Answer 1

To calculate the equilibrium concentration of I from the reaction with a Kc of 0.0011 and [I2] of 0.10 M, you can use the expression Kc = [I]^2/[I2] and solve for [I].

Step-by-step explanation:

The subject of the question is in the field of Chemistry, specifically related to chemical equilibrium and the calculation of equilibrium concentrations. To find the equilibrium concentration of I for the reaction I2 (g) ⇌ 2I (g) with a given Kc of 0.0011 and a known concentration of I2 of 0.10 M, the equilibrium expression Kc = [I]2/[I2] is used. Let's simply represent the equilibrium concentration of I as x. So, we have 0.0011 = x2/0.10. By solving this equation for x, we find that x = sqrt(0.0011 * 0.10), which gives the equilibrium concentration of I in moles per liter.