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A photon has a energy of 2.93 x 10^-25 j. what is the photons wavelength? what type of electromagnetic radiation is it?

User Sasho
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Final answer:

To calculate the wavelength of a photon with energy 2.93 x 10^-25 J, use the equation λ = hc/E which results in a wavelength of 676 nm, indicating that the photon is part of the visible light spectrum, specifically near the red end.

Step-by-step explanation:

To determine the wavelength of a photon from its energy, we can use the equation that links these two properties: E = hc/λ, where E is the energy, h is Planck's constant (6.626 x 10-34 J·s), c is the speed of light (3.00 x 108 m/s), and λ is the wavelength.

Solving for λ gives λ = hc/E. Plugging in the values, we get λ = (6.626 x 10-34 J·s)(3.00 x 108 m/s) / (2.93 x 10-25 J) = 6.76 x 10-7 meters or 676 nm.

This wavelength falls in the visible light spectrum, specifically close to the red end. So, the type of electromagnetic radiation this photon represents is visible light.

User TessavWalstijn
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