Question

The equilibrium constant kc for the following reaction is 0.223. n2o4(g) ⇄ 2 no2(g) what is the equilibrium constant for 4no2(g) ⇄ 2n2o4(g)

Answer 1

The equilibrium constant for the reverse reaction 4 NO2(g) ⇌ 2 N2O4(g) is the reciprocal of the square of the original equilibrium constant, which equals 20.18.

Step-by-step explanation:

The equilibrium constant for the reaction N2O4(g) ⇌ 2 NO2(g) is provided as 0.223. When the reaction is written in reverse, the equilibrium constant expression is also reversed. Thus, the equilibrium constant for the reaction 4 NO2(g) ⇌ 2 N2O4(g) would be the reciprocal of the original equilibrium constant. Since the reaction is doubled, the original equilibrium constant, Kc, should be squared and then its reciprocal should be taken. Therefore, the new equilibrium constant Kc will be equal to 1/0.2232.

Calculating this value yields Kc= 1 / (0.2232) = 20.18.