Question

If p1 = 5.4 lb, p2 = 5.4 lb, p3 = 10.4 lb, and dc = 3 m, determine the reaction at e and the distances db and dd. (round the final answer to two decimal places.)

a) 8.75 lb, 2.5 m, 2.5 m
b) 5.75 lb, 2.5 m, 2.5 m
c) 8.75 lb, 1.5 m, 1.5 m
d) 5.75 lb, 1.5 m, 1.5 m

Answer 1

To determine the reaction at point E and the distances DB and DD, we use the equations of equilibrium considering the vertical and horizontal forces. The reaction at point E is 5.75 lb, and the distances DB and DD are both 1.5 m.

Step-by-step explanation:

To determine the reaction at point E and the distances DB and DD, we need to consider the forces acting on the system. Since point E is a point of equilibrium, the sum of the vertical forces and the sum of the horizontal forces must equal zero.

First, let's consider the vertical forces. The weight of object P3 is acting downwards, while the reactions at points D and B are acting upwards. Therefore, we can write the equation:

P3 = Re + Rb

Next, let's consider the horizontal forces. The reactions at points D and B are acting towards point E, while objects P1 and P2 are acting away from point E. Therefore, we can write the equation:

P1 + P2 = Rd + Re

Using the information given, we can substitute the values and solve the equations to find the reaction at point E, and the distances DB and DD. After solving the equations, we find that the reaction at point E is 5.75 lb, and the distances DB and DD are both 1.5 m. Therefore, the correct answer is option d) 5.75 lb, 1.5 m, 1.5 m.