Question

If an object accelerates from rest, what will its velocity be after 12.3 seconds if it has a constant acceleration of 4.6 m/s²

a) 56.58 m/s
b) 45.58 m/s
c) 34.58 m/s
d) 23.58 m/s

Answer 1

Using the kinematic equation v = u + at, the object's velocity after 12.3 seconds with a constant acceleration of 4.6 m/s² is found to be 56.58 m/s.

Step-by-step explanation:

If an object accelerates from rest with a constant acceleration of 4.6 m/s², we can calculate its velocity after 12.3 seconds using one of the kinematic equations for uniformly accelerated motion, which is:

v = u + at

where:

• v = final velocity
• u = initial velocity (which is zero since the object is at rest)
• a = acceleration
• t = time

By substituting the known values into the equation, we get:

v = 0 + (4.6 m/s²)(12.3 s)

v = 56.58 m/s

Therefore, the correct answer is a) 56.58 m/s.