Final answer:
The concentration of the dilute sugar solution, after diluting a 5.05 M sugar solution from 230.0 mL to 675.0 mL, is found to be 1.7207 M. This is calculated using the molarity equation M1V1 = M2V2.
Step-by-step explanation:
To calculate the concentration of the dilute sugar solution, we can use the dilution equation M1V1 = M2V2, where:
- M1 = initial molarity (concentration) of the solution
- V1 = initial volume of the solution
- M2 = final molarity (concentration) of the dilute solution
- V2 = final volume of the solution
Substitute the given values into the equation:
M1 = 5.05 M (initial molarity)
V1 = 230.0 mL (initial volume)
V2 = 675.0 mL (final volume)
The final molarity (M2) can be calculated as follows:
M2 = (M1 × V1) / V2
M2 = (5.05 M × 230.0 mL) / 675.0 mL
M2 = 1.7207 M
The concentration of the dilute sugar solution is 1.7207 M.
Comparing this to a similar calculation example: If a 355-mL soft drink sample contains 0.133 mol of sucrose, the molarity is calculated by dividing the moles of sucrose by the volume in liters.
Molarity of sucrose in the soft drink = 0.133 mol / 0.355 L = 0.375 M.