Final answer:
To determine the number of moles of aluminum sulfate formed from a given number of moles of aluminum bromide, we need to use the balanced chemical equation and stoichiometry. In this case, the answer is 2.325 mol.
Step-by-step explanation:
To determine the number of moles of aluminum sulfate formed from a given number of moles of aluminum bromide, we need to use the balanced chemical equation for the reaction between aluminum bromide (AlBr₃) and aluminum sulfate (Al₂(SO₄)₃). The balanced equation is:
2 AlBr₃ + 3 H₂SO₄ → Al₂(SO₄)₃ + 6 HBr
From the equation, we can see that 2 moles of AlBr₃ react to form 1 mole of Al₂(SO₄)₃. Therefore, if 4.65 moles of AlBr₃ are used, we can calculate the number of moles of Al₂(SO₄)₃ formed as follows:
4.65 moles AlBr₃ x (1 mole Al₂(SO₄)₃ / 2 moles AlBr₃) = 2.325 moles Al₂(SO₄)₃
Therefore, the answer is 2.325 mol.