Question

Shown below is a 59 kg crate that is pushed up a 30° incline by the horizontal force f. the magnitude of the horizontal force is 614 n, and after being pushed 8.9 m, the crate's speed is 7.5 m/s. how much work (in j) is done by the force of friction? assume that the crate starts at rest.

Answer 1

The work done by the force of friction can be calculated using the equation Work = Force x Distance x cos(angle). Substitute the given values to find the work done by the applied force, which is equal to the work done by the force of friction. The work done by the force of friction in this case is -95.75 J.

Step-by-step explanation:

To calculate the work done by the force of friction, we need to first find the work done by the horizontal force applied to the crate. The work done by a force is given by the equation:

Work = Force x Distance x cos(angle)

Given that the crate is pushed 8.0 m up the incline, and the magnitude of the horizontal force is 614 N, we can substitute these values into the equation:

Work = 614 N x 8.0 m x cos(30°)

Calculating this gives us the work done by the applied force, which is then equal to the work done by the force of friction as the crate comes to a stop. This work is equal to -95.75 J.