Question

Calculate the actual, physiological delta g for the reaction at 37 c as it occurs in cytoskeleton of neurons

Answer 1

To calculate the physiological delta G for a reaction in a neuron's cytoskeleton, the free energy change equation involving standard free energy change, concentrations in steady state, and temperature in Kelvin is used. Specific values for these variables are required to perform the calculation.

Step-by-step explanation:

Physiological Delta G Calculation for Reaction in Neuron's Cytoskeleton

To calculate the actual, physiological delta G (ΔG') for a reaction as it occurs in the cytoskeleton of neurons, you must use the following equation:

To calculate the actual, physiological ΔG (Gibbs free energy change) for a reaction at 37°C, you would typically use the formula:

`\[ \Delta G = \Delta G^\circ + RT \ln(Q) \]`

where:

• 
  `\( \Delta G \)` is the actual Gibbs free energy change,
• 
  `\( \Delta G^\circ \)` is the standard Gibbs free energy change,
• 
  `\( R \)` is the ideal gas constant
  `(\(8.314 \, \text{J/(mol} \cdot \text{K)}\)),`
• 
  `\( T \)` is the temperature in Kelvin
  `(37^oC = 310^oK)`,
• 
  `\( Q \)` is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants at any point during the reaction.

The standard Gibbs free energy change
`(\( \Delta G^\circ \))` can be obtained from tables of standard Gibbs free energies of formation for the reactants and products.

It's important to note that the actual ΔG for a reaction in a living organism is influenced by factors such as the actual concentrations of reactants and products inside the cell, as well as the influence of cellular conditions. These conditions may differ from standard conditions, and thus, the actual physiological ΔG can be different from the standard value.

Without specific information on the reaction and concentrations involved, it's challenging to provide a numerical value for the actual physiological ΔG. If you have more details about the reaction and the concentrations, I can assist you further.