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Humans can bite with a force of approximately 810 n. if a human tooth has the young's modulus of bone, a cross-sectional area of 1.1 cm2, and is 1.6 cm long, determine the change in the tooth's length during an 8.10 ✕ 102 n bite.

User Florian M
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Final answer:

To determine the change in a human tooth's length during an 810 N bite, one needs to apply the formula ΔL = FL / (A * E) using the force, original length, cross-sectional area, and Young's modulus for bone.

Step-by-step explanation:

This is asking about the elasticity and deformation of a human tooth under a biting force, applying concepts from physics, specifically the topic of elasticity and Young's modulus. To calculate the change in length of the tooth during a bite, one must use Hooke's Law in the form of the equation ΔL = FL / (A * E), where ΔL is the change in length, F is the force applied, L is the original length of the tooth, A is the cross-sectional area of the tooth, and E is Young's modulus of the material (which, for bone, the student can find in a physics book or online resource). The given values are: Force (F): 8.10 × 102 N, Original length (L): 1.6 cm, Cross-sectional area (A): 1.1 cm2, You would also need Young's modulus (E) for human bone, which the student can look up. By substituting these values into the equation, the student can calculate the change in the tooth's length when a force of approximately 810 N is applied during a bite.

User Achraf Amil
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