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How much 0.075 M NaCl solution can be made by diluting 450 mL of 9.0 M NaCl? (1L = 1000 mL)

a) Calculate the volume of the dilute solution.
b) Determine the molarity of the dilute solution.

User Andre
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1 Answer

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Final answer:

The volume of 0.075 M NaCl solution that can be made by diluting 450 mL of 9.0 M NaCl is 54 L. The molarity of the dilute solution remains as given, which is 0.075 M.

Step-by-step explanation:

The subject of this question is Chemistry, specifically involving the concept of molarity and dilution of solutions. When you're diluting a solution, the amount of solute in the solution remains the same, but the volume it occupies increases.



To answer part (a) of the student's question:

  • You have 450 mL of a 9.0 M NaCl solution initially.
  • To find the volume of the diluted solution (V2), you can use the dilution equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of the concentrated solution and M2 and V2 are the molarity and volume of the diluted solution respectively.
  • Plugging in the known values, we have (9.0 M)(450 mL) = (0.075 M)(V2).
  • Solving for V2, we find that V2 = (9.0 M)(450 mL) / 0.075 M.
  • After performing the calculation, we find that V2 = 54,000 mL or 54 L.



So, part (a) - the volume of the 0.075 M diluted solution that can be made is 54 liters.



To answer part (b) of the student's question:

  • The molarity of the dilute solution, as asked by the student, remains constant in this process as per the design of the question. It is given as 0.075 M.

User Nicolas Heimann
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