Final answer:
To determine the volume of NH₃ produced from a given amount of nitrogen gas and an excess of hydrogen gas, we can use stoichiometry and the ideal gas law equation. Approximately 2.4 liters of NH₃ can be produced.
Step-by-step explanation:
To determine the volume of NH₃ produced from a given amount of nitrogen gas and an excess of hydrogen gas, we can use the concept of stoichiometry. According to the balanced chemical equation N₂(g) + 3H₂(g) ⟶ 2NH₃(g), the ratio between nitrogen and ammonia is 1:2.
First, we need to convert the mass of nitrogen gas to moles using its molar mass (28 g/mol). Then, using the mole ratio, we can calculate the moles of ammonia produced. Finally, we can convert the moles of ammonia to liters using the ideal gas law equation V = nRT/P, where V is the volume in liters, n is the number of moles, R is the gas constant, T is the temperature in Kelvin, and P is the pressure in atmospheres.
Plugging in the values and solving for V, we get:
V = (2 mol)(0.0821 L·atm/mol·K)(297 K)/(5 atm) ≈ 2.37 L
Therefore, approximately 2.4 liters of NH₃ can be produced.