Question

How much energy in kJ is required to heat a calorimeter whose heat capacity is 117.8 J from 23.5°C to 79.3°C?

24.5 kJ
35.2 kJ
42.1 kJ
55.8 kJ

Answer 1

The energy required to heat a calorimeter with a heat capacity of 117.8 J/°C from 23.5°C to 79.3°C is 6.57 kJ, which is calculated using the formula q = C × ΔT.

Step-by-step explanation:

To calculate the energy required to heat a calorimeter, we use the formula q = C × ΔT, where q is the heat energy, C is the heat capacity of the calorimeter, and ΔT is the change in temperature. The heat capacity of the calorimeter is given as 117.8 J/°C, and we need to heat it from 23.5°C to 79.3°C, which is a temperature change (ΔT) of 79.3°C - 23.5°C = 55.8°C. Applying the formula, we get: q = 117.8 J/°C × 55.8°C = 6573.24 J. Since 1 kJ = 1000 J, converting this into kJ gives us 6.57324 kJ, which we can round to 6.57 kJ. Among the provided options, none matches this correct calculation, so we need to ensure we select the correct answer based on the actual calculation rather than matching it with the provided options.