Final answer:
The force exerted by a 0.25 kg apple with an acceleration of 9.8 m/s² is 2.45 N, calculated using the formula F = m × a.
Step-by-step explanation:
The force exerted by a 0.25 kg apple when it experiences an acceleration of 9.8 m/s² can be calculated using Newton's second law of motion, which states that force equals mass times acceleration (F = m × a). To find the force, we multiply the mass of the apple (0.25 kg) by the acceleration due to gravity (9.8 m/s²).
F = m × a = 0.25 kg × 9.8 m/s² = 2.45 N.
Therefore, the force exerted by the apple is 2.45 N.