Final answer:
To neutralize the given volume of NaOH, we can use the concept of stoichiometry and the formula M1V1 = M2V2. The number of milliliters of HClO4 solution needed is 31.5 mL.
Step-by-step explanation:
To find the number of milliliters of 0.132 M HClO4 solution needed to neutralize 50.00 mL of 0.0832 M NaOH, we can use the concept of stoichiometry.
First, we need to determine the molar ratio between HClO4 and NaOH. From the balanced equation:
HClO4 + NaOH -> NaClO4 + H2O
we can see that the ratio is 1:1.
Next, we can use the formula:
M1V1 = M2V2,
Where M1 and V1 are the concentration and volume of the HClO4 solution, and M2 and V2 are the concentration and volume of the NaOH solution.
Plugging in the values:
(0.132 M)(V1) = (0.0832 M)(50.00 mL)
Solving for V1:
V1 = (0.0832 M)(50.00 mL) / 0.132 M
V1 = 31.5 mL
Therefore, the correct answer is a. 31.5 mL.