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One ball is drawn from a bag containing 8 red balls numbered 1–8 and 9 white balls numbered 9–17. Find the probability that it is white and odd-numbered.

a) 1/17

b) 1/9

c) 1/8

d) 9/17



1 Answer

3 votes

Final answer:

The probability of drawing a white, odd-numbered ball from a bag containing 8 red balls and 9 white balls is 5/17. This is because there are 5 odd-numbered white balls and 17 balls in total, but this answer is not amongst the given options, suggesting a possible error in the question.

Step-by-step explanation:

The question asks us to find the probability of drawing a white and odd-numbered ball from a bag containing 8 red balls numbered 1–8 and 9 white balls numbered 9–17. To solve this, we first need to identify the total number of possible outcomes and the number of favorable outcomes. There are a total of 8 + 9 = 17 balls in the bag, which makes our sample space equal to 17.

Next, we need to determine how many white balls are odd-numbered. The white balls are numbered 9 through 17. The odd numbers in this range are 9, 11, 13, 15, and 17, for a total of 5 odd white balls.

Therefore, the probability of drawing a white, odd-numbered ball is the number of odd, white balls divided by the total number of balls. This is 5/17, which is not one of the options provided. If the options are assumed to be correct, this is likely an error in the question or the provided options.

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