Question

On a certain hot summer's day, 559 people use the public swimming pool. The daily prices are $1.75 for children and $2.50 for adults. The receipts for admission totaled $1,177. How many children and how many adults swam at the public pool that day?

A) Children: 275, Adults: 284
B) Children: 200, Adults: 359
C) Children: 320, Adults: 239
D) Children: 250, Adults: 309

Answer 1

There were 293 children and 266 adults who swam at the public pool that day. However, this does not match any of the provided options, indicating a possible error in the options or the problem's setup.

Step-by-step explanation:

To solve this problem we can set up a system of equations. Let's use C to represent the number of children and A to represent the number of adults. We have two pieces of information that lead to two equations:

• The total number of people is 559, so C + A = 559.
• The total amount of money collected is $1177, so 1.75C + 2.50A = 1177.

Now we can solve these equations simultaneously to find the values of C and A.

Step 1: Solve the first equation for C

C = 559 - A

Step 2: Substitute C in the second equation

1.75(559 - A) + 2.50A = 1177

Step 3: Distribute and combine like terms

977.25 + 0.75A = 1177

Step 4: Solve for A

A = (1177 - 977.25) / 0.75

A = 266

Step 5: Solve for C using A = 266

C = 559 - 266

C = 293

Therefore, there were 293 children and 266 adults who swam at the public pool that day. This information aligns with none of the provided options A) through D), suggesting there may be a mistake in the options or the initial problem setup.