Question

On a playground, there is a merry-go-round. In order to get it moving, Bonnie applies a force of 35 N. The merry-go-round measures 9.1 m from the axis of rotation to the edge where Bonnie applies her force. Assuming she applies her force perpendicularly to a line drawn from the axis of rotation, what is the magnitude of the torque (T) Bonnie imparts to the merry-go-round?

A) 319.5 N

B) 318.5 N

C) 352 N

D) 330.5 N

Answer 1

Bonnie imparts a torque of 318.5 N•m to the merry-go-round by applying a force of 35 N, at a distance of 9.1 m from the axis, perpendicular to the radius.

Step-by-step explanation:

To calculate the torque (T) imparted by Bonnie to the merry-go-round, we use the formula for torque, which is given by T = r * F, where r is the radius, or the distance from the axis of rotation to the point where the force is applied, and F is the force applied perpendicularly to the radius.

In this scenario, Bonnie applies a force of 35 N, and the radius (distance from the axis to the edge where the force is applied) is 9.1 m. By substituting these values into the torque formula, we get T = 9.1 m * 35 N = 318.5 N·m. Therefore, the magnitude of the torque Bonnie imparts to the merry-go-round is 318.5 N·m, which corresponds to option B.