Question

Which expression is equivalent to "28p⁹q⁻⁵/12p⁻⁶q⁷"?

Assume "p=0, q=0".
a. "84p¹⁵q²"
b. "24p¹⁵q²"
c. "168p³q²"
d. "48p³q²"

Answer 1

To simplify the expression 28p⁹q⁻⁵/12p⁻⁶q⁷, we can combine the coefficients and variables with the same base. The equivalent expression is
`(7/3)p^1^5/q^1^2`.

Step-by-step explanation:

To simplify the expression 28p⁹q⁻⁵/12p⁻⁶q⁷, we can combine the coefficients and variables with the same base.

The coefficient 28 divided by 12 simplifies to 7/3.

For the variable p, we subtract the exponents, which gives us
`p^(^9^-^(^-^6^))` =
`p^1^5`.

For the variable q, we subtract the exponents, which gives us
`q^(^-^5^-^7^)` =
`q^(^-^1^2^)` =
`1/q^1^2`.

Putting all of this together, we get the equivalent expression
`(7/3)p^1^5/q^1^2`.