Question

What are the solutions to the equation ? List your answers in increasing order. If applicable, type your answers in decimal form and do not include a leading zero.

a) No real solutions
b) √2, -√2
c) 1, -1
d) Insufficient information provided

Answer 1

The solutions to the equation can be found using the quadratic formula. The solutions are -15.684 and 5.684.

Step-by-step explanation:

The solutions to the equation can be found using the quadratic formula. Given the equation:

ax^2 + bx + c = 0

where a = 1.00, b = 10.0, and c = -200, we can substitute these values into the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values into the formula, we have:

x = (-10.0 ± √(10.0^2 - 4(1.00)(-200))) / (2(1.00))

Simplifying this expression gives us two solutions:

x = -15.684

and

x = 5.684

Therefore, the solutions to the equation are -15.684 and 5.684.