Question

Consider the hydrate iron (ii) sulfate heptahydrate (feso4 · 7h2o) when answering the questions below. Type in the molar masses using two decimal places. What is the molar mass of the anhydrous salt feso4? g/mol what is the molar mass of water in this hydrate? g/mol what is the molar mass of this hydrate? g/mol

Answer 1

The molar mass of FeSO4 is 151.91 g/mol, the molar mass of water in FeSO4 · 7H2O is 18.02 g/mol, and the molar mass of the hydrate FeSO4 · 7H2O is 278.05 g/mol.

Step-by-step explanation:

The molar mass of the anhydrous salt FeSO4 can be calculated by summing the atomic masses of iron (Fe), sulfur (S), and oxygen (O). Using atomic masses Fe (55.85 g/mol), S (32.07 g/mol), and O (16.00 g/mol), the molar mass of FeSO4 is:

FeSO4 = 55.85 + 32.07 + (4 × 16.00) = 151.91 g/mol

The molar mass of water (H2O) is simply the sum of the atomic masses of hydrogen (H) and oxygen (O), with the molar mass being:

2H + O = (2 × 1.01) + 16.00 = 18.02 g/mol

To calculate the molar mass of the hydrate iron (ii) sulfate heptahydrate (FeSO4 · 7H2O), you add the molar mass of the anhydrous salt to the mass of seven water molecules:

FeSO4 · 7H2O = 151.91 + (7 × 18.02) = 278.05 g/mol