Question

Three balls labeled 1, 2, and 3 are launched horizontally from the Leaning Tower of Pisa with the trajectories shown below. Balls 1 and 2 are launched from the top floor, which is 40 m from the ground, while ball 3 is launched from the middle floor, which is 20 m from the ground. We can ignore air resistance. Find the distance between 3 balls.

Answer 1

Answer:
vball2 < vball1 < vball3

Step-by-step explanation:

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Answer 2

To find the distance between the three balls, subtract the initial horizontal velocity multiplied by the time it takes for ball 3 to hit the ground from the horizontal distance for balls 1 and 2.

Step-by-step explanation:

To find the distance between the three balls, we need to consider their horizontal distances from the Leaning Tower of Pisa. The horizontal distances for balls 1 and 2 are the same since they are launched from the same height. The horizontal distance for ball 3 will be different since it is launched from a different height.

Since all three balls have the same horizontal acceleration of 0 m/s^2 (ignoring air resistance), we can use the equation: distance = velocity * time. The time it takes for each ball to hit the ground will be the same, assuming they are launched with the same initial horizontal velocity.

Therefore, to find the distance between the three balls, we can subtract the initial horizontal velocity multiplied by the time it takes for the ball to hit the ground for ball 3 from the horizontal distance for balls 1 and 2.