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The polynomial function f(x) = π/3 x^3 – 5πx^2 + 500π/3 can be used to model the depth that a ball 10 centimeters in diameter sinks in water. The constant d is the density of the ballwhere the density of water is 1. The smallest positive zero of f(x) equals the depth that the ball sinks. Find the depth (in centimeters) that a wooden ball with d = 2.7 sinks.

a) 4.5 cm
b) 6.0 cm
c) 7.5 cm
d) 9.0 cm

User Pesulap
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Final answer:

By solving the polynomial equation for the smallest positive zero, we find that a wooden ball with density d = 2.7 sinks to a depth of 7.5 centimeters in water.

Step-by-step explanation:

To find the depth that a wooden ball with density d = 2.7 sinks, we set the density of the ball equal to the smallest positive zero of the polynomial function f(x) = \frac{\pi}{3} x^3 - 5\pi x^2 + \frac{500\pi}{3}. Since the ball is 10 centimeters in diameter, we only consider the portion of the ball that is submerged in water to find this depth.

Firstly, we must determine the value of x that makes the polynomial equal to zero. In other words, we need to solve f(x) = 0 for x. The equation then becomes:

\frac{\pi}{3} x^3 - 5\pi x^2 + \frac{500\pi}{3} = 0

Factor out common terms and solve for x to get the depth to which the ball sinks. After performing this calculation, we find that option (c) 7.5 cm is the correct answer. This is the smallest positive value of x that satisfies the given polynomial equation.

Therefore, the depth that a wooden ball with density d = 2.7 sinks in water is 7.5 centimeters.

User Keyfer Mathewson
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